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4m^2-25m+6=0
a = 4; b = -25; c = +6;
Δ = b2-4ac
Δ = -252-4·4·6
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-23}{2*4}=\frac{2}{8} =1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+23}{2*4}=\frac{48}{8} =6 $
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